we did bring in an Algebriac Identity for comparison purposes :
and proceeded to solve for a pair of values for [ T ] and [ U ] satisfying the 2 Conditions ,
is a solution value to the reformatted { 3rd-Order Polynomial Equation } .
And on re-arranging terms , we had :
Cubing both sides then yielded us this equation :
and substituted therein the result we have immediately above to yield :
And on re-arranging terms , we had :
And on adding [ N-square ] to both sides of the equation , we had :
Consequently :
We then have :
or alternately :
so that we would then attempt to solve for [ T ] and [ U ] via 2 different routes , namely :
Let us now recall these results from the last Section - Section XXXVI :
Consequently , we can now write :
Therefore :
As a result :
And because we have already established above :
and
it then follows that :
And because we have already established above :
and
it then follows that :