- For our analysis here on the [ relative positions ] of the 20 [ pieces ] :
- we shall first select at random any one of of the 20 [ pieces ] as the [ Base Piece ] of our analysis .
And we shall also immediately identify the [ Opposite Piece ] , being the [ piece ] directly-opposite to the [ Base Piece ] .
- We then present this set of 3 diagrams below :
- showing the [ Base Piece ] as marked-off in [ magenta-color ] , and
- showing the [ Opposite Piece ] as marked-off in [ purple-color ] .

- We then construct a straight-line passing-thru the [ centroidal-points ] of the two (2) said-[ pieces ] ,
- and this then is the [ Axis-Of-Tri-Symmetry ] for our [ 1-3-6-6-3-1 Split ] configuration to follow .
- And for better viewing and easier-to-understand purposes , let us now re-orient the entire Icosahedron , so that :
- the [ Axis-of-Tri-Symmetry ] is now in a [ quasi-upright ] position ,
- as per this set of 3 diagrams below .

- We shall next identify the 4 layers situated in-between the [ Base Piece ] and the [ Opposite Piece ] , namely :
- the [ 1st Layer-Of-Three ] ,
- the [ 1st Layer-Of-Six ] ,
- the [ Opposite Layer-Of-Six ] , and
- the [ Opporsite Layer-Of-Three ] .
We shall now do the following :
- identify the 3 [ pieces ] adjacent to the [ Base Piece ] as the [ 1st Layer-Of-Three ] ,
- identify the 3 [ pieces ] adjacent to the [ Opposite Piece ] as the [ Opposite Layer-Of-Three ] ,
We then have this set of 3 diagrams :
- showing the 3 [ pieces ] in the [ 1st Layer-Of-Three ] in [ orange-color ] , and
- showing the 3 [ pieces ] in the [ Opposite Layer-Of-Three ] in [ brown-color ] .

And we simply note here that :
- For the 3 [ pieces ] in the [ 1st Layer-Of-Three ] :
- these are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] , and
- their [ centriodal-points ] are equi-distant from the [ centroidal-point ] of the [ Base Piece ] .
- For the 3 [ pieces ] in the [ Opposite Layer-Of-Three ] :
- these are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] , and
- their [ centriodal-points ] are equi-distant from the [ centroidal-point ] of the [ Opposite Piece ] .
And this arises from the triple-but-equivalent adjacency :
- of the 3 [ orange-color pieces ] to the one-and-the-same [ Base Piece ] ,
- of the 3 [ brown-color pieces ] to the one-and-the-same [ Opposite Piece ] .
- Let us now identify the [ 1st Layer-Of-Six ] consisting of :

- the 6 [ pieces ] are then the 6 [ pieces ] adjacent to the 3 [ orange-color pieces ] .
Let us now combine the 2 sets of diagrams for a full view of the 6 [ pieces ] in the [ 1st Layer-Of-Six ] :

We simply note here that :
- the 3 [ light-green-color pieces ] are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] ,
- the 3 [ cornflower-blue-color pieces ] are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] , and
- the 6 [ centroidal-points ] of the 6 [ pieces ] are equi-distant from the [ centroidal-point ] of the [ Base Piece ] ,
And to understand why this is so , let us recall 2 things here :
- First , for any one of the 3 tri-symmetric [ orange-color pieces ] ,
- the 3 adjacent [ pieces ] are always the [ magenta / light-green / cornflower-blue pieces ] , and :
- the [ circulra counter-clockwise rotation-order ] here is always [ magenta-lightgreen-cornflowerblue ] .

As such , the 3 adjacent [ pieces ] are always tri-symmetric about the [ orange-color piece ] so that :
- the [ centroidal-points ] of the [ magenta / light-green / cornflower-blue pieces ] always form an Equilateral Triangle .
It then follows from the Equilateral Triangle that :
- the [ centrodial-points ] of the [ light-green / cornflower-blue pieces ] are always equi-distant from the [ centroidal-point ] of the [ magenta-color piece ] .
- Secondly , the tri-symmetric nature of the 3 [ orange-color pieces ] necessarily dictates :
- the [ tri-symmetric nature ] of the 3 [ light-green-color pieces ] , and
- the [ tri-symmetric nature ] of the 3 [ cornflower-blue-color pieces ] ;
given the fact that :
- Let us now identify the [ Opposite Layer-Of-Six ] consisting of :

- the 6 [ pieces ] are then the 6 [ pieces ] adjacent to the 3 [ brown-color pieces ] .
Let us now combine the 2 sets of diagrams for a full view of the 6 [ pieces ] in the [ Opposite Layer-Of-Six ] :

We simply note here that :
- the 3 [ dark-green-color pieces ] are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] ,
- the 3 [ cyan-color pieces ] are [ tri-symmetric ] about the [ Axis-Of-Tri-Symmetry ] , and
- the 6 [ centroidal-points ] of the 6 [ pieces ] are equi-distant from the [ centroidal-point ] of the [ Opposite Piece ] ,
And to understand why this is so , let us recall 2 things here :
- First , for any one of the 3 tri-symmetric [ brown-color pieces ] ,
- the 3 adjacent [ pieces ] are always the [ purple / dark-green / cyan pieces ] , and :
- the [ circular counter-clockwise rotation-order ] here is always [ purple-darkgreen-cyan ] .

As such , the 3 adjacent [ pieces ] are always tri-symmetric about the [ brown-color piece ] so that :
- the [ centroidal-points ] of the [ purple / dark-green / cyan pieces ] always form an Equilateral Triangle .
It then follows from the Equilateral Triangle that :
- the [ centrodial-points ] of the [ dark-green / cyan pieces ] are always equi-distant from the [ centroidal-point ] of the [ purple-color piece ] .
- Secondly , the tri-symmetric nature of the 3 [ brown-color pieces ] necessarily dictates :
- the [ tri-symmetric nature ] of the 3 [ dark-green-color pieces ] , and
- the [ tri-symmetric nature ] of the 3 [ cyan-color pieces ] ;
given the fact that :
- This then completes the [ 1-3-6-6-3-1 Split ] of the 20 [ pieces ] comprising of :
- the [ Base Piece ] ,
- the [ 1st Layer-Of-Three ] ,
- the [ 1st Layer-Of-Six ] ,
- the [ Opposite Layer-Of-Six ] ,
- the [ Opposite Layer-Of-Three ] , and
- the [ Opposite Piece ] .
