And , for our purpose of counting { Category X numbers } here ,
involving [ N ] , the { 9th-power-of-[ 2 ] } , and their quotient [ 3.02 ] .
We can then quickly establish , from our [ Table of Prime Numbers ] ,
and also :
And we take note here that :
and
And what this tells us here then is that :
will involve a [ prime factor ] greater than the prime-number [ 3 ] .
We can then establish :
Consequently , we can now sub-divide the { Category X numbers } in-question here into ten (10) sub-groups :
The count here for Stage I is therefore [ 2 ] .
We note here that :
and all 8 numbers above are already greater than [ N = 1543 ] .