And this is based on our Fast-Track Procedure to identify { prime numbers } in Section VII .
And we shall use [ 31 ] as the { pivotal prime number } here ; so that :
And the { Product-of-Primes } we shall use at this instance , denoted by [ N ] here , is then :
| Range | Candidates for Prime Numbers | Comments | ||||||
|---|---|---|---|---|---|---|---|---|
| ****************** | ********** | ********** | ********** | ********** | ********** | ********** | ****************** | ************** |
| 1 thru [ N ] | 1 | 31 | 37 | 41 | 43 | 47 | { Set C } | base row |
| [ N + 1 ] thru [ 2*N ] | N + 1 | N + 31 | N + 37 | N + 41 | N + 43 | N + 47 | N + { Set C } | candidate row |
| [ 2*N + 1 ] thru [ 3*N ] | 2*N + 1 | 2*N + 31 | 2*N + 37 | 2*N + 41 | 2*N + 43 | 2*N + 47 | 2*N + { Set C } | candidate row |
| [ 3*N + 1 ] thru [ 4*N ] | 3*N + 1 | 3*N + 31 | 3*N + 37 | 3*N + 41 | 3*N + 43 | 3*N + 47 | 3*N + { Set C } | candidate row |
| .......... | And so-on-and-so-forth | candidate rows | ||||||
| [ 29*N + 1 ] thru [ 30*N ] | 29*N + 1 | 29*N + 31 | 29*N + 37 | 29*N + 41 | 29*N + 43 | 29*N + 47 | 29*N + { Set C } | candidate row |
| [ 30*N + 1 ] thru [ 31*N ] | 30*N + 1 | 30*N + 31 | 30*N + 37 | 30*N + 41 | 30*N + 43 | 30*N + 47 | 30*N + { Set C } | candidate row |
There are then three ( 3 ) possible scenario's here :
( in-between the { next prime number lower than [ x*N + 1 ] } and the { next prime number higher than [ x*N + 31 ] } ) .
And once we have identified the value of [ P ] , we immediately know for sure that :
there exists a gap in-between 2 consecutive { prime numbers } that is greater than or equal to [ Q ] .
( replace [ 31 ] with any { prime number greater than [ 5 ] } and follow the exact-same procedure ) .
And that is to say :